0=(x^2)+1.5x-115

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Solution for 0=(x^2)+1.5x-115 equation:



0=(x^2)+1.5x-115
We move all terms to the left:
0-((x^2)+1.5x-115)=0
We add all the numbers together, and all the variables
-(x^2+1.5x-115)=0
We get rid of parentheses
-x^2-1.5x+115=0
We add all the numbers together, and all the variables
-1x^2-1.5x+115=0
a = -1; b = -1.5; c = +115;
Δ = b2-4ac
Δ = -1.52-4·(-1)·115
Δ = 462.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{462.25}}{2*-1}=\frac{1.5-\sqrt{462.25}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{462.25}}{2*-1}=\frac{1.5+\sqrt{462.25}}{-2} $

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